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12x^2-8.4=0
a = 12; b = 0; c = -8.4;
Δ = b2-4ac
Δ = 02-4·12·(-8.4)
Δ = 403.2
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-\sqrt{403.2}}{2*12}=\frac{0-\sqrt{403.2}}{24} =-\frac{\sqrt{}}{24} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+\sqrt{403.2}}{2*12}=\frac{0+\sqrt{403.2}}{24} =\frac{\sqrt{}}{24} $
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